Q. The angular resolution of a $10\ cm$ diameter telescope at a wavelength of$\ 5000\ \mathring{\mathrm{A}}$ is of the order
A) $10^{6}rad$
B) $10^{- 2}rad$
C) $10^{- 4}\ rad$
D) $10^{- 6}\ rad$
Explanation
(d) Angular resolution $d\theta = \frac{1.22\ \lambda}{a}$
$= \frac{1.22 \times 5000 \times 10^{- 10}}{10 \times 10^{- 2}} = 6.1 \times 10^{- 6}rad$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.