(a) When the final image is formed at infinity by a telescope, it is called in normal adjustment and then length of the telescope is given by
$L = f_{0}\ + f_{e}$
Where $f_{0}$ is the focal length of objective lens and $f_{e}$ is the focal length of eye-piece
$\therefore L = \ f_{0} + f_{e} = 0.3 + 0.05 = 0.35\ m$