Q. A vessel of depth 2d $cm$ is half filled with a liquid of refractive index $\mu_{1}$ and the upper half with a liquid of refractive index $\mu_{2}$. The apparent depth of the vessel seen perpendicularly is
A) $d\left( \frac{\mu_{1}\mu_{2}}{\mu_{1} + \mu_{2}} \right)$
B) $d\left( \frac{1}{\mu_{1}} + \frac{1}{\mu_{2}} \right)$
C) $2d\left( \frac{1}{\mu_{1}} + \frac{1}{\mu_{2}} \right)$
D) $2d\left( \frac{1}{\mu_{1}\mu_{2}} \right)$
Explanation
(b) $h^{'} = \frac{d_{1}}{\mu_{1}} + \frac{d_{2}}{\mu_{2}} = d\left( \frac{1}{\mu_{1}} + \frac{1}{\mu_{2}} \right)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.