Q. With diaphragm of the camera lens set at $f/2,\ $the correct exposure time is 1/100s. Then with diaphragm set at $f/8,$ the correct exposure time is

A) 1/100 s
B) 1/400 s
C) 1/200 s
D) 16/100 s
Explanation

(d) $t \propto \frac{f^{2}}{d^{2}}$
$\frac{f}{d}\ $means that the diameter of aperture is $\frac{f}{2}$
Now,$\ \frac{1}{100} \propto \frac{f^{2}}{\left( \frac{f}{2} \right)^{2}}$
Or $\frac{1}{100} \propto 4\ \ $…(i)
Again, $t \propto \frac{f^{2}}{\left( \frac{f}{8} \right)^{2}}$
Or $\ \ t \propto 64$ …(ii)
Dividing Eq.(ii) by Eq.(i)
$100t = \frac{64}{4} = 16\ or\ t = \frac{16}{100}s$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.