(b) $\mu = \frac{c}{v}$ $\therefore\frac{\mu}{\mu'} = \frac{v'}{v}$ $\frac{1.5}{1.8} = \frac{v'}{2 \times 10^{8}}$ $v^{'} = \frac{3 \times 10^{8}}{1.8} = 1.67 \times 10^{8}{ms}^{- 1}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.