A convex lens is immersed in a liquid, whose refractive index is equal to the refractive index of the material of the lens. Then its focal length will

Question

Dr. Abubacker · Accepted Answer

(c) Given, $\ _{a}\mu_{g} = \ _{a}\mu_{e}$
The focal length of convex lens in liquid $f$ is given by
$\frac{1}{f} = \left( \frac{\ _{a}\mu_{g}}{\ ₐ\ _{a}\mu_{e}ₑ} - 1 \right)\left( \frac{1}{R_{1}} - \frac{1}{R_{2}} \right)$
$\frac{1}{f} = (1 - 1)\left( \frac{1}{R_{1}} - \frac{1}{R_{2}} \right)\ $
$\frac{1}{f} = 0$
$Or\ \ f = \ \infty$
Its focal length will become infinite.

Q. A convex lens is immersed in a liquid, whose refractive index is equal to the refractive index of the material of the lens. Then its focal length will

Explanation

Reviewed by Dr. Abubacker

Want more practice?