Q. An object 15 cm high is placed 10 cm from the optical centre of a thin lens. Its image is formed 25 cm from the optical centre on the same side of the lens as the object. The height of the image is
A) 2.5 cm
B) 0.2 cm
C) 16.7 cm
D) 37.5 cm
Explanation
(d) $\frac{I}{O} = \frac{v}{u}$
$\frac{I}{15} = \frac{- 25}{- 10}$
$I = 15 \times 2.5\ cm = 37.5\ cm$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.