Q. A plane mirror is approaching you at $10\ cms^{- 1}$. Your image shall approach you will a speed of
A) $+ 10$ $cms^{- 1}$
B) $- 10\ cms^{- 1}$
C) $+ \ 20\ cms^{- 1}$
D) $- 20\ cms^{- 1}$
Explanation
(c) [image:9_image127.emf]
As is clear from figure, the new distance is $2x - 2v.\ $The distance of image from object is reduced by an amount $2v$ is one second
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.