Q. An electromagnetic wave, going through vacuum is described by $E = E_{0}\sin{(kx - \omega t)}$. Which of the following is independent of wavelength
A) $k$
B) $\omega$
C) $k/\omega$
D) $k\omega$
Explanation
(c) The angular wave number $k = \frac{2\pi}{\lambda}$; where $\lambda$ is the wave length. The angular frequency is $w = 2\pi v$
The ratio $\frac{k}{\omega} = \frac{2\pi/\lambda}{2\pi v} = \frac{1}{v\lambda} = \frac{1}{c} =$ constant
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.