If we observe the single slit Frunhofer diffraction with wavelength $\lambda$ and slit width e, the width of the central maxima is $2 heta$. On decreasing the slit width for the same $\lambda$

Question

If we observe the single slit Frunhofer diffraction with wavelength $\lambda$ and slit width e, the width of the central maxima is $2	heta$. On decreasing the slit width for the same $\lambda$

Dr. Abubacker · Accepted Answer

(a) The diffraction pattern of light waves of wavelength $(\lambda)$ diffracted by a single, long narrow slit of width is shown. For first minimum.
$e\sin	heta = \lambda$
$\sin	heta = \frac{\lambda}{e}$
[image:10_image24.emf]
When $e$ is decreased for same wavelength, $\sin	heta$ increases, hence $	heta$ increases. Thus, width of central maxima will increase.

Q. If we observe the single slit Frunhofer diffraction with wavelength $\lambda$ and slit width e, the width of the central maxima is $2\theta$. On decreasing the slit width for the same $\lambda$

Explanation

Reviewed by Dr. Abubacker

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