In a Young’s double slit experiment using red and blue lights of wavelengths 600 nm and 480 nm respectively, the value of $n$ from which the $n^{th}$ red fringe coincides with $(n + 1)$ the blue fringe is

Question

Dr. Abubacker · Accepted Answer

(b) $n\lambda_{r} = (n + 1)\lambda_{b}$
$\frac{n + 1}{n} = \frac{\lambda_{r}}{\lambda_{b}} = \frac{600}{480} = \frac{4}{5}$
$\frac{1}{n} = \frac{4}{5} - 1 = \frac{1}{4}n = 4$

Q. In a Young’s double slit experiment using red and blue lights of wavelengths 600 nm and 480 nm respectively, the value of $n$ from which the $n^{th}$ red fringe coincides with $(n + 1)$ the blue fringe is

Explanation

Reviewed by Dr. Abubacker

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