A plane wave of wavelength 6250$\ \mathring{\mathrm{A}}$ is incident normally on a slit of width $2 imes 10^{- 2}$ cm. The width of the principal maximum on a screen distant 50 cm will be

Question

A plane wave of wavelength 6250$\ \mathring{\mathrm{A}}$ is incident normally on a slit of width $2 	imes 10^{- 2}$ cm. The width of the principal maximum on a screen distant 50 cm will be

Dr. Abubacker · Accepted Answer

(a) Here, $\lambda = 6250\ \mathring{\mathrm{A}} = 6250 	imes 10^{- 10}m$
$a = 2 	imes 10^{- 2}cm = 2 	imes 10^{- 4}m$
$D = 50\ cm = 0.5\ m$
Width of central maximum=$\frac{2\lambda D}{a}$
$= \frac{2 	imes 6250 	imes 10^{- 10} 	imes 0.5}{2 	imes 10^{- 4}}$
$312.5 	imes 10^{- 3}\ cm$

Q. A plane wave of wavelength 6250$\ \mathring{\mathrm{A}}$ is incident normally on a slit of width $2 \times 10^{- 2}$ cm. The width of the principal maximum on a screen distant 50 cm will be

Explanation

Reviewed by Dr. Abubacker

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