(d) $E = \frac{hc}{\lambda} = \frac{6.6 \times 10^{- 34} \times 3 \times 10^{8}}{21 \times 10^{- 2}} = 0.94 \times 10^{- 24} = 10^{- 24}J$
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Ph.D. in Physics with 19+ years of teaching experience.