Q. Fringes are obtained with the help of a biprism in the focal plane of an eyepiece distance 1 m from the slit. A convex lens produces images of the slit in two positions between biprism and eyepiece. The distances between two images of the slit in two positions are$4.05 \times 10^{- 3}$m and $2.90 \times 10^{- 3}$m respectively. The distance between the slits will be
A) $3.43 \times 10^{- 3}$m
B) $0.343$m
C) $0.0343$m
D) $43.3$m
Explanation
(a) Distance between the slits,
$d = \sqrt{d_{1}d_{2}} = \sqrt{4.05 \times 10^{- 3} \times 2.90 \times 10^{- 3}}$
$= 3.427 \times 10^{- 3}m$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.