Q. Light of wavelength 6000 $\ \mathring{\mathrm{A}}$ falls on a single slit of width 0.1 mm. The second minimum will be formed for the angle of diffraction of
A) 0.08 rad
B) 0.06 rad
C) 0.12 rad
D) 0.012 rad
Explanation
(d) Given single slit of width $d = 0.1\ mm$
$d = 0.1 \times 10^{- 3}\ m$
Or $d = 1 \times 10^{- 4}\ m$
Light of wavelength $a = 600\ \mathring{\mathrm{A}}$
Or $\alpha = 6 \times 10^{- 7}\ m$
The angle of diffraction
$\theta = \frac{n\lambda}{d}$
$\theta = \frac{2 \times 6 \times 10^{- 7}}{1 \times 10^{- 4}}$
$\theta = {12 \times 10}^{- 3}$
$\theta = 0.012\ rad$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.