Q. In Young’s double slit experiment, the length if band is 1 mm. The ring width is 1.021 mm. The number of fringe is

A) 45
B) 46
C) 47
D) 48
Explanation

(c) The number of fringes on either side of centre C of screen is
$n_{1} = \left\lbrack \frac{AC}{\beta} \right\rbrack = \left\lbrack \frac{0.5}{0.021} \right\rbrack = \lbrack 23.8\rbrack = 23$
$\therefore$ Total number of fringes
$= 2n_{1} + fringe\ at\ centre$
$= 2n_{1} + 1 = 2 \times 23 + 1$
$= 46 + 1 = 47$
In Young’s experiment, the number of fringes should be odd.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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