Q. An electromagnetic wave going through vacuum is described by $E = E_{0}\sin{(kx - \omega t);B = B_{0}}\sin{(kx - \omega t)}$. Which of the following equations is true
A) $E_{0}k = B_{0}\omega$
B) $E_{0}\omega = B_{0}k$
C) $E_{0}B_{0} = \omega k$
D) None of these
Explanation
(a) $\frac{E_{0}}{B_{0}} = c$. also $k = \frac{2\pi}{\lambda}$ and $\omega = 2\pi v$
These relation gives $E_{0}k = B_{0}\omega$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.