A parallel beam of monochromatic light of wavelength $5000\ \mathring{\mathrm{A}}$ is incident normally on a single narrow slit of width $0.001mm$. The light is focused by a convex lens on a screen placed on the focal plane. The first minimum will be formed for the angle of diffraction equal to

Question

Dr. Abubacker · Accepted Answer

(c) For the first minima $d\sin	heta = \lambda$
$\Rightarrow \sin	heta = \frac{\lambda}{d} \Rightarrow 	heta = \sin^{- 1}{\left( \frac{5000 	imes 10^{- 10}}{0.001 	imes 10^{- 3}} ight) = 30{^\circ}}$

Q. A parallel beam of monochromatic light of wavelength $5000\ \mathring{\mathrm{A}}$ is incident normally on a single narrow slit of width $0.001mm$. The light is focused by a convex lens on a screen placed on the focal plane. The first minimum will be formed for the angle of diffraction equal to

Explanation

Reviewed by Dr. Abubacker

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