Q. In Young’s double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is
A) $\sin^{- 1}{(0.01)}$
B) $\sin^{- 1}{(0.0001)}$
C) $\sin^{- 1}{(0.001)}$
D) $\sin^{- 1}{(0.1)}$
Explanation
(c) In Youngs’s double slit experiment half angular width is given by
$\sin{\theta = \frac{\lambda}{d}}$
$\ \ \ \ \ \ \ \ \ \ = \frac{589 \times 10^{- 9}}{0.589 \times 10^{- 3}} = 10^{- 3}$
$\Rightarrow \ \theta = \sin^{- 1}{(0.001)}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.