Q. Intensities of the two waves of light are $I$ and $4I$. The maximum intensity of the resultant wave after superposition is
A) $5\ I$
B) $9\ I$
C) $16\ I$
D) $25\ I$
Explanation
(b) $I_{\max} = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}}$
So, $I_{\max} = I + 4I + 2\sqrt{I.4I} = 9I$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.