(d) Let $I_{1} = a^{2},\ I_{2} = b^{2}$ $\therefore\ \ I_{\max} = (a + b)^{2} = a^{2} + b^{2} + 2ab$ $= I_{1} + I_{2} + 2\sqrt{I_{1}}\sqrt{I_{2}} = \left( \sqrt{I_{1}} + \sqrt{I_{2}} \right)^{2}$
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Ph.D. in Physics with 19+ years of teaching experience.