In Young’s double slit experiment, the 7$^{th}$ maximum wavelength $\lambda_{1}$ is at a distance $d_{1}$ and that with wavelength $\lambda_{2}$ is at a distance $d_{2}$.Then $\left( d_{1}/d_{2} \right)$ is

Question

Dr. Abubacker · Accepted Answer

(a) From $x = n\lambda\frac{D}{d}$
$d_{1} = 7\lambda_{1}\frac{D}{d}$
$d_{2} = 7\lambda_{2}\frac{D}{d}$
$	herefore\frac{d_{1}}{d_{2}} = \frac{\lambda_{1}}{\lambda_{2}}$

Q. In Young’s double slit experiment, the 7$^{th}$ maximum wavelength $\lambda_{1}$ is at a distance $d_{1}$ and that with wavelength $\lambda_{2}$ is at a distance $d_{2}$.Then $\left( d_{1}/d_{2} \right)$ is

Explanation

Reviewed by Dr. Abubacker

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