Light if wavelength $2 imes 10^{- 3}$ m falls on a slit of width $4 imes 10^{- 3}$ m. The angular dispersion of the central maximum will be

Question

Light if wavelength $2 	imes 10^{- 3}$ m falls on a slit of width $4 	imes 10^{- 3}$ m. The angular dispersion of the central maximum will be

Dr. Abubacker · Accepted Answer

(b) Angular dispersion of central maximum=angular dispersion of 1st minimum $( = 2	heta)$
From $\sin{	heta = \frac{1\lambda}{a} = \frac{2 	imes 10^{- 3}}{4 	imes 10^{- 3}} = \frac{1}{2}}$
$	heta = 30{^\circ}$
$	herefore 2	heta = 2 	imes 30{^\circ} = 60{^\circ}$

Q. Light if wavelength $2 \times 10^{- 3}$ m falls on a slit of width $4 \times 10^{- 3}$ m. The angular dispersion of the central maximum will be

Explanation

Reviewed by Dr. Abubacker

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