(c) Fringe width $\beta = 2\ mm = 2 \times 10^{- 3}\ m$ $\ \ \lambda = 6000\ \mathring{\mathrm{A}}$ $\mu = 1.33$ $\beta^{'} = \ ?$ $\beta^{'} = \frac{\beta}{\mu} = \frac{2}{1.33} = 1.5\ mm$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.