The fringe width a distance of 50 cm from the slits in Young’s experiment for light of wavelength 6000 $\mathring{\mathrm{A}}$ is 0.048 cm. The fringe width at the same distance for $\lambda = 5000\ \mathring{\mathrm{A}}$ will be

Question

Dr. Abubacker · Accepted Answer

(a) $\beta^{'} = \frac{\lambda^{'}}{\lambda}\beta = \frac{5000}{6000} 	imes 0.48 = 0.04$cm

Q. The fringe width a distance of 50 cm from the slits in Young’s experiment for light of wavelength 6000 $\mathring{\mathrm{A}}$ is 0.048 cm. The fringe width at the same distance for $\lambda = 5000\ \mathring{\mathrm{A}}$ will be

Explanation

Reviewed by Dr. Abubacker

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