The equations of displacement of two waves are given as $y_{1} = 10\sin(3\pi t + \pi/3)$ $y_{2} = 5\left( \sin{3\pi t + \sqrt{3}\cos{3\pi t}} \right)$, then what is the ratio of their amplitude?

Question

Dr. Abubacker · Accepted Answer

(c) Here, $a = 10,\ b = \sqrt{5^{2} + \left( 5\sqrt{3} ight)^{2}} = 10$
$	herefore\ \frac{a}{b} = \frac{10}{10} = 1:1$

Q. The equations of displacement of two waves are given as $y_{1} = 10\sin(3\pi t + \pi/3)$ $y_{2} = 5\left( \sin{3\pi t + \sqrt{3}\cos{3\pi t}} \right)$, then what is the ratio of their amplitude?

Explanation

Reviewed by Dr. Abubacker

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