Q. What is the minimum thickness of a thin film required for constructive interference in the reflected light from it? Given, the refractive index of the film = 1.5, wavelength of the light incident on the film = 600 nm

A) 100 nm
B) 300nm
C) 50 nm
D) 200 nm
Explanation

(a) Condition for constructive interference is
$2\mu t = \lbrack 2n + 1\rbrack\frac{\lambda}{2}$
Where, $n = 0,\ 1,\ 2,\ 3,\ \ldots\ldots$
For minimum thickness, $n = 0$
$2\mu t = \frac{\lambda}{2}$
$\Rightarrow t = \frac{\lambda}{4\mu} = \frac{600 \times 10^{- 9}}{4 \times 1.5} = 100\ nm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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