Q. In a diffraction pattern by a wire, on increasing diameter of wire, fringe width
A) Decreases
B) Increases
C) Remains unchanged
D) Increasing or decreasing will depend on wavelength
Explanation
(a) $\beta = \frac{\lambda.D}{d}$ where $D =$ distance of screen from wire, $d =$ diameter of wire
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.