(d) $\mu_{0} = 4\pi \times 10^{- 7},\ \varepsilon_{0} = 8.85 \times 10^{- 12}\frac{N - m^{2}}{C^{2}}$ So $c = \frac{1}{\sqrt{\mu_{0}\varepsilon_{0}}} = 3 \times 10^{8}\frac{meter}{second}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.