In Young’s double slit experiment if the slits widths are in the ratio 1 : 9, the ratio of the intensities at minima to that at maxima will be

Question

Dr. Abubacker · Accepted Answer

(c) Amplitude of the superimposing waves are
$\frac{a_{1}}{a_{2}} = \left( \frac{1}{9} \right)^{1/2} = \frac{1}{3}$
$\frac{I_{minima}}{I_{maxima}} = \frac{\left( a_{1} - a_{2} \right)^{2}}{\left( a_{1} + a_{2} \right)^{2}} = \frac{1}{4}$

Q. In Young’s double slit experiment if the slits widths are in the ratio 1 : 9, the ratio of the intensities at minima to that at maxima will be

Explanation

Reviewed by Dr. Abubacker

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