$nth$ Bright fringe if red light $\left( \lambda_{1} = 7500\ \mathring{\mathrm{A}} \right)$ coincides with $(n + 1)^{th}$ bright fringe of green light$\left( \lambda_{2} = 6000\ \mathring{\mathrm{A}} \right)$. The value of $n =$?

Question

Dr. Abubacker · Accepted Answer

(a) As the two bright fringes coincide
$	herefore\ \ n\lambda_{1} = (n + 1)\lambda_{2}$
$\frac{n + 1}{n} = \frac{\lambda_{1}}{\lambda_{2}} = \frac{7500}{6000} = \frac{5}{4}$
$1 + \frac{1}{n} = \frac{5}{4},n = 4$

Q. $nth$ Bright fringe if red light $\left( \lambda_{1} = 7500\ \mathring{\mathrm{A}} \right)$ coincides with $(n + 1)^{th}$ bright fringe of green light$\left( \lambda_{2} = 6000\ \mathring{\mathrm{A}} \right)$. The value of $n =$?

Explanation

Reviewed by Dr. Abubacker

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