Q. In an apparatus, the electric field was found to oscillate with an amplitude of $18\ V/m$. The magnitude of the oscillating magnetic field will be
A) $4 \times 10^{- 6}T$
B) $6 \times 10^{- 8}T$
C) $9 \times 10^{- 9}T$
D) $11 \times 10^{- 11}T$
Explanation
(b) $c = \frac{E}{B} \Rightarrow B = \frac{E}{c} = \frac{18}{3 \times 10^{8}} = 6 \times 10^{- 8}T$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.