Q. The Young’s double slit experiment is performed with blue and with green light of wavelengths 4360$\ \mathring{\mathrm{A}}$ and $5460\ \mathring{\mathrm{A}}$ respectively. If $x$ is the distance of 4$^{th}$ maximum from the central one, then
A) $x(blue) = x\ (green)$
B) $x(blue) > x\ (green)$
C) $x(blue) < x\ (green)$
D) $\frac{x(blue)}{x(green)}\ .\frac{5460}{4360}$
Explanation
(c) Position of fourth maxima
$x_{0} = \frac{4D\lambda}{d}$
Or $x \propto \lambda$
$\therefore\ x(blue) < \ x(green)$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.