Q. What will be the angular width of central maxima in Fraunhoffer diffraction when light of wavelength $6000\mathring{\mathrm{A}}$ is used and slit width is $12 \times 10^{- 5}cm$
A) $2\ rad$
B) $3\ rad$
C) $1\ rad$
D) $8\ rad$
Explanation
(c) Angular width $= \frac{2\lambda}{d} = \frac{2 \times 6000 \times 10^{- 10}}{12 \times 10^{- 5} \times 10^{- 2}} = 1rad$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.