Q. In Young’s experiment, the ratio of maximum to minimum intensities of the fringe system is 4:1. The amplitudes of the coherent sources are in the ratio

A) 4 : 1
B) 3 : 1
C) 2 : 1
D) 1 : 1
Explanation

(b) $\frac{I_{\max}}{I_{\min}} = \frac{\left( \frac{a_{1}}{a_{2}} + 1 \right)^{2}}{\left( \frac{a_{1}}{a_{2}} - 1 \right)^{2}} = \frac{4}{1} \Rightarrow \frac{a_{1}}{a_{2}} = \frac{3}{1}$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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