Light of wavelength $589.3nm$ is incident normally on the slit of width $0.1nm$. What will be the angular width of the central diffraction maximum at a distance of $1m$ from the slit

Question

Dr. Abubacker · Accepted Answer

(a) Angular width of central maxima
$= \frac{2\lambda}{d} = \frac{2 	imes 589.3 	imes 10^{- 9}}{0.1 	imes 10^{- 3}}rad$
$= 0.0117 	imes \frac{180}{\pi} = 0.68{^\circ}$

Q. Light of wavelength $589.3nm$ is incident normally on the slit of width $0.1nm$. What will be the angular width of the central diffraction maximum at a distance of $1m$ from the slit

Explanation

Reviewed by Dr. Abubacker

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