Q. Microwaves from a transmitter are directed normally towards a plane reflector. A detector moves along the normal to the reflector. Between positions of 14 successive maxima, the detector travels a distance of 0.14 m. The frequency of transmitter is
A) $1.5 \times 10^{10}H$
B) $10^{10}H$
C) $3 \times 10^{10}H$
D) $6 \times 10^{10}H$
Explanation
(c) Distance between two successive maxima
$\lambda = \frac{0.14}{14}m = 10^{- 2}m,$
$v = \frac{c}{\lambda} = \frac{3 \times 10^{8}}{10^{- 2}} = 3 \times 10^{10}H\ $
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.