(c) $x = (n + 1)\lambda_{b} = n\lambda_{r}$ $\frac{n + 1}{n} = \frac{\lambda_{r}}{\lambda_{b}} = \frac{7.8 \times 10^{- 5}}{5.2 \times 10^{- 5}} = \frac{3}{2}$ $1 + \frac{1}{b} = \frac{3}{2}$ $n = 2$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.