Q. In Young’s double slit experiment, the intensity of light coming from the first slit is double the intensity from the second slit. The ratio of the maximum intensity to the minimum intensity on the interference fringe pattern observed is
A) 34
B) 40
C) 25
D) 38
Explanation
(a) $\frac{I_{\max}}{I_{\min}} = \left( \frac{\sqrt{\frac{I_{1}}{I_{2}}} + 1}{\sqrt{\frac{I_{1}}{I_{2}}} - 1} \right)^{2} = \left( \frac{\sqrt{2} + 1}{\sqrt{2} - 1} \right)^{2} = 34;\lbrack Given\ I_{1} = 2I_{2}\rbrack$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.