Q. The equations of two interfering waves are $y_{1} = b\cos{\omega t}$ and$y_{2} = b\cos{(\omega t + \phi)}$. For destructive interference the path difference is

A) $0{^\circ}$
B) $360{^\circ}$
C) $180{^\circ}$
D) $720{^\circ}$
Explanation

(c) For destructive interference, path difference$= \frac{\lambda}{2}$.
Therefore, phase difference$= \frac{2\pi}{\lambda}.\frac{\lambda}{2} = \pi$ radian=$180{^\circ}$.

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

Want more practice?
Practice Wave Optics MCQs