Q. The magnetic field amplitude of an electromagnetic wave is $2 \times 10^{- 7}T$. It’s electric field amplitude if the wave is travelling in free space is :
A) $6Vm^{- 1}$
B) $60Vm^{- 1}$
C) $10/6Vm^{- 1}$
D) None of these
Explanation
(a) $c = \frac{E_{0}}{B_{0}} =$ speed of light
$\Rightarrow E_{0} = B_{0}c$
Given, $B_{0} = 2 \times 10^{- 7}T,\ c = 3 \times 10^{8}m/s$
$E_{0} = 2 \times 10^{- 7} \times 3 \times 10^{8} = 60T\ m/s = 60\ Vm^{- 1}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.