Q.
A single slit of width $a$ is illuminated by violet light of wavelength $400\ nm$ and the width of the diffraction pattern is measured as $y$. When half of the slit width is covered and illuminated by yellow light of wavelength $600\ nm$, the width of the diffraction pattern is
A) The pattern vanishes and the width is zero
B) $y/3$
C) $3y$
D) None of these
Explanation
(c) In single slit experiment,
Width of central maxima $(y) = 2\lambda D/d$
$\Rightarrow \frac{y^{'}}{y} = \frac{\lambda^{'}}{d^{'}} \times \frac{d}{\lambda} = \frac{600}{d/2} \times \frac{d}{400} \Rightarrow y^{'} = 3y$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.