In Young’s double slit experiment, the aperture screen distance is 2 m. The slit width is 1 mm. Light of 600 nm is used. If a thin plate of glass $(\mu - 1.5)$ of thickness 0.06 mm is placed over one of the slits, then there will be a lateral displacement of the fringes by

Question

Dr. Abubacker · Accepted Answer

(b) When a thin glass plate of thickness t is placed over one of the slits, then lateral displacement is given by
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$x = \frac{(\mu - 1)tD}{d}$
Given, $\ \mu = 1.5,\ t = 0.06\ mm = 6 	imes 10^{- 5}\ m$
$D = 2\ m,\ d = 1\ mm = 1 	imes 10^{- 3}\ m$
Putting the values in the above relation, we get
$x = \frac{(1.5 - 1) 	imes 6 	imes 10^{- 5} 	imes 2}{1 	imes 10^{- 3}}$
$= {0.5 	imes 12 	imes 10}^{- 2} = 0.06\ m = 6cm$

Q. In Young’s double slit experiment, the aperture screen distance is 2 m. The slit width is 1 mm. Light of 600 nm is used. If a thin plate of glass $(\mu - 1.5)$ of thickness 0.06 mm is placed over one of the slits, then there will be a lateral displacement of the fringes by

Explanation

Reviewed by Dr. Abubacker

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