(c) Resultant intensity $I = 4I_{0}\cos^{2}{(\phi/2)}$ $\Rightarrow \frac{I_{1}}{I_{2}} = \frac{\cos^{2}{(\phi_{1}/2)}}{\cos^{2}{(\phi_{2}/2)}} = \frac{\cos^{2}0}{\cos^{2}{(90/2)}} = \frac{2}{1}$
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.