Q. The condition for obtaining secondary maxima in the diffraction pattern due to single slit is
A) $a\sin\theta = n\lambda$
B) $a\sin\theta = (2n - 1)\frac{\lambda}{2}$
C) $a\sin\theta = (2n - 1)\lambda$
D) $a\sin\theta = \frac{n\lambda}{2}$
Explanation
The correct answer is Option B: $a\sin\theta = (2n - 1)\frac{\lambda}{2}$.
A detailed explanation for this question is being prepared.
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.