In a Young’s double slit experiment the intensity at a point where the path difference is $\frac{\lambda}{6}(\lambda$ being the wavelength of the light used) is $I$. If $I_{0}$ denotes the maximum intensity, $\frac{I}{I_{0}}$ is equal to

Question

Dr. Abubacker · Accepted Answer

(d) $\frac{I}{I_{0}} = \cos^{2}{\left( \frac{\phi}{2} \right);\phi = \frac{2\pi}{\lambda}.\Delta x}$

Q. In a Young’s double slit experiment the intensity at a point where the path difference is $\frac{\lambda}{6}(\lambda$ being the wavelength of the light used) is $I$. If $I_{0}$ denotes the maximum intensity, $\frac{I}{I_{0}}$ is equal to

Explanation

Reviewed by Dr. Abubacker

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