Q. In the Young’s double slit experiment, the central maxima are observed to be$I_{0}$. If one of the slits is covered, then the intensity at the central maxima will become
A) $\frac{I_{0}}{2}$
B) $\frac{I_{0}}{\sqrt{2}}$
C) $\frac{I_{0}}{4}$
D) $I_{0}$
Explanation
(a) Intensity, $I_{0} = I_{1} + I_{2} + 2\ \sqrt{I_{1}I_{2}}$
If $I_{1} = I_{2} = I(Let)$
Then $I_{0} = 4I$
When one slit is covered then $I_{2} = 0$
$\therefore I_{0}^{'} = I = \frac{I_{0}}{4}$
Reviewed by Dr. Abubacker
Physics Educator & NEET/JEE Specialist
Ph.D. in Physics with 19+ years of teaching experience.