Light of wavelength $500nm$ is used to form interference pattern in Young’s double slit experiment. A uniform glass plate of refractive index 1.5 and thickness $0.1nm$ is introduced in the path of one of the interfering beams. The number of fringes which will shift the cross wire due to this is

Question

Dr. Abubacker · Accepted Answer

(a) The number of fringes shifting is decided by the extra path difference produced by introducing the glass plate. The extra path difference is $(\mu - 1)t = n\lambda$
Or $(1.5 - 1) 	imes 0.1 	imes 10^{- 3} = n 	imes 500 	imes 10^{- 9}$
$\Rightarrow n = 100$

Q. Light of wavelength $500nm$ is used to form interference pattern in Young’s double slit experiment. A uniform glass plate of refractive index 1.5 and thickness $0.1nm$ is introduced in the path of one of the interfering beams. The number of fringes which will shift the cross wire due to this is

Explanation

Reviewed by Dr. Abubacker

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