(b) From $I_{R} = I_{1} + I_{2} + 2\sqrt{I_{1}I_{2}}\cos\phi$
When $\phi = 0{^\circ},\ I_{R} = I + I + 2\sqrt{II}\cos{0{^\circ} = 4I}$
When $\phi = 90{^\circ}$
$I_{R}^{'} = I + I + 2\sqrt{II}\cos{90{^\circ} = 2I}$
$\frac{I_{R}}{I_{R}^{'}} = \frac{4I}{2I} = 2:1$