Q. In an interference pattern the position of zeroth order maxima is 4.8 mm from a certain point $P$ on the screen. The fringe width is 0.2 mm. The position of second maxima from point $P$ is

A) 5.1 mm
B) 5 mm
C) 40 mm
D) 5.2 mm
Explanation

(a) The distance between zeroth order maxima and second order minima is
$y_{1} = \frac{\beta}{2} + \beta = \frac{3}{2}\beta$
$= \frac{3}{2} \times 0.2\ mm = 0.3\ mm$
$\therefore$ The distance of second maxima from point P is
$y = (4.8 + 0.3)mm = 5.1\ mm$

Dr. Abubacker
Reviewed by Dr. Abubacker

Physics Educator & NEET/JEE Specialist

Ph.D. in Physics with 19+ years of teaching experience.

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